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數學問題超極難函數問題
1.定義函數f(n)=【n 3
當n為奇數】 【n除以2
當n為偶數】例如：f(1)=4
f(2)=1
f(3)=6
f(4)=2......若f(9)=A1
f(A1)=A2
f(A2)=A3
...........
f(Am)=f(Am 1)
f(A2012)=?2.z是自然數
f(z)=1*(2z─1) 2*(2z─3) ............ (z─1)*3 z*1則f(50) ─ f(49)=?f(30)=? (請寫出正確數值)
(1)A1 = f(9) = 9 3 = 12A2 = f(A1) = f(12) = 12/2 = 6A3 = f(A2) = f(6) = 6/2 = 3A4 = f(A3) = f(3) = 3 3 = 6 = A2A5 = f(A4) = f(6) = 3 = A3. . .所以
如果 m
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